Factorise of the following : $64 a^{3}-27 b^{3}-144 a^{2} b+108 a b^{2}$

Vedclass pdf generator app on play store
Vedclass iOS app on app store

$64 a^{3}-27 b^{3}-144 a^{2} b+108 a b^{2}=(4 a)^{3}-(3 b)^{3}-3(4 a)(3 b)[4 a-3 b]$

                                                                    $=(4 a-3 b)^{3}$                $[$ Using Identity $VII]$

                                                                   $=(4 a-3 b)(4 a-3 b)(4 a-3 b)$

Similar Questions

Write the following cubes in expanded form : $(2 x+1)^{3}$

Evaluate the following using suitable identities : $(99)^{3}$

Factorise the following using appropriate identities : $4 y^{2}-4 y+1$

Verify whether the following are zeroes of the polynomial, indicated against them.

$p(x)=5 x-\pi, \,\,x=\frac{4}{5}$

Find the remainder when $x^4+x^3-2x^2+x+1$ is divided by $x -1$.